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Square root of Kretschmann scalar in Schwarzschild metric

Дата публикации: 27-07-2026 13:18:37



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  • Thread starter Thread starter Roberto Pavani
  • Start date Start date Jul 26, 2026
Roberto Pavani
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TL;DR
Any known references where ##\sqrt{K}## rather than ##K## is used as a geometric quantity?
In Schwarzschild vacuum, the Kretschmann scalar is

##K = R_{abcd}R^{abcd} = \frac{48M^2}{r^6}##

I notice that ##\sqrt{K}## has dimensions of ##[\text{length}]^{-2}## and a clean ##1/r^3## profile.

Has ##\sqrt{K}## (as opposed to ##K## itself) appeared in any published work as a physically meaningful quantity? I'm aware of ##K## being used for singularity detection and invariant classification, but
I'm curious whether the square root has ever been studied separately.

Thanks for any references.

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QuarkyMeson
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I found this: https://link.springer.com/article/10.1140/epjc/s10052-024-13204-8

Having the dimensions of an energy density does not make something an energy density, any more than having dimensions of acceleration makes something an observable acceleration. Soooo, it all feels a bit like numerology to me and less like physics.

Markus Hanke
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I found this: https://link.springer.com/article/10.1140/epjc/s10052-024-13204-8

Having the dimensions of an energy density does not make something an energy density, any more than having dimensions of acceleration makes something an observable acceleration. Soooo, it all feels a bit like numerology to me and less like physics.


While dimensional analysis is merely a guide,
it obviously has to be followed up with seeing if
it (obtained from a scalar formed from the riemann tensor) helps characterize quantities of physical interest.

I'm not an astrophysicist, but this seems to do that:

What does a measurement of mass and/or radius of a neutron star constrain: Equation of state or gravity?
Kazim Yavuz Ekşi, Can Güngör, Murat Metehan Türkoğlu
Phys. Rev. D 89, 063003 – Published 6 March, 2014
https://doi.org/10.1103/PhysRevD.89.063003
https://arxiv.org/abs/1402.0488

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I'm not an astrophysicist, but this seems to do that:

What does a measurement of mass and/or radius of a neutron star constrain: Equation of state or gravity?
Kazim Yavuz Ekşi, Can Güngör, Murat Metehan Türkoğlu
Phys. Rev. D 89, 063003 – Published 6 March, 2014
https://doi.org/10.1103/PhysRevD.89.063003
https://arxiv.org/abs/1402.0488


It seems this paper is exactly what @Roberto Pavani asked for -- a publish paper which uses the square root of the full contraction of the Riemann tensor:
Indeed, it seems they use the square root to define the Kretschmann scalar in the first place.

I'm not sure why it matters whether we use the full contraction itself or its square root though?

Roberto Pavani
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Thank you all for the references.

In fact, my original curiosity came from the observation that, in Schwarzschild vacuum,

## \mathcal{K} \equiv \sqrt{R^{\mu\nu\alpha\beta}R_{\mu\nu\alpha\beta}}
=
\frac{4\sqrt{3}\,GM}{c^2 r^3}. ##

I was therefore interested in whether this quantity had ever been considered independently of the Kretschmann scalar itself.

The references posted above are very helpful because they show that the square root of the Kretschmann scalar has indeed been used as a physically meaningful measure of spacetime curvature, gravitational field strength, or effective gravitational energy density.

That is exactly the kind of prior literature I was hoping to find, so thank you.

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postscript (other curvature invariants that could be given a similar treatment):

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